11m^2+45m=0

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Solution for 11m^2+45m=0 equation: 



11m^2+45m=0

a = 11; b = 45; c = 0;
Δ = b2-4ac
Δ = 452-4·11·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$


$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-45}{2*11}=\frac{-90}{22}
=-4+1/11
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+45}{2*11}=\frac{0}{22}
=0
$

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